Very complex math question goes here
2-1= 1 is for losers.
cos2 (x) + sin2 (x) = (eix + e-ix )2 /4 + sin2 (x) = (e2ix + e-2ix )/4 + e2ln(sin(x)) + 1/2 =1
or
int_{0} ^ {π/2} {x * prod_{j = 1} ^ {∞} {cos(x / 2j )}} dx
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